Integrand size = 24, antiderivative size = 107 \[ \int \frac {x^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {a^2}{4 b^3 (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {2 a}{3 b^3 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {1}{2 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}} \]
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Time = 0.03 (sec) , antiderivative size = 107, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {660, 45} \[ \int \frac {x^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {a^2}{4 b^3 (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {2 a}{3 b^3 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {1}{2 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}} \]
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Rule 45
Rule 660
Rubi steps \begin{align*} \text {integral}& = \frac {\left (b^4 \left (a b+b^2 x\right )\right ) \int \frac {x^2}{\left (a b+b^2 x\right )^5} \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}} \\ & = \frac {\left (b^4 \left (a b+b^2 x\right )\right ) \int \left (\frac {a^2}{b^7 (a+b x)^5}-\frac {2 a}{b^7 (a+b x)^4}+\frac {1}{b^7 (a+b x)^3}\right ) \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}} \\ & = -\frac {a^2}{4 b^3 (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {2 a}{3 b^3 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {1}{2 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}} \\ \end{align*}
Time = 0.67 (sec) , antiderivative size = 187, normalized size of antiderivative = 1.75 \[ \int \frac {x^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\frac {x^3 \left (-4 a^6-a^5 b x+3 a b^5 x^5+4 a^4 \sqrt {a^2} \sqrt {(a+b x)^2}-3 a^3 \sqrt {a^2} b x \sqrt {(a+b x)^2}-3 a \sqrt {a^2} b^3 x^3 \sqrt {(a+b x)^2}+3 \sqrt {a^2} b^2 x^2 \sqrt {(a+b x)^2} \left (a^2+b^2 x^2\right )\right )}{12 a^6 (a+b x)^3 \left (\sqrt {a^2} b x+a \left (\sqrt {a^2}-\sqrt {(a+b x)^2}\right )\right )} \]
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Time = 2.15 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.35
method | result | size |
gosper | \(-\frac {\left (b x +a \right ) \left (6 b^{2} x^{2}+4 a b x +a^{2}\right )}{12 b^{3} \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}}}\) | \(37\) |
default | \(-\frac {\left (b x +a \right ) \left (6 b^{2} x^{2}+4 a b x +a^{2}\right )}{12 b^{3} \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}}}\) | \(37\) |
risch | \(\frac {\sqrt {\left (b x +a \right )^{2}}\, \left (-\frac {x^{2}}{2 b}-\frac {a x}{3 b^{2}}-\frac {a^{2}}{12 b^{3}}\right )}{\left (b x +a \right )^{5}}\) | \(42\) |
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Time = 0.24 (sec) , antiderivative size = 65, normalized size of antiderivative = 0.61 \[ \int \frac {x^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {6 \, b^{2} x^{2} + 4 \, a b x + a^{2}}{12 \, {\left (b^{7} x^{4} + 4 \, a b^{6} x^{3} + 6 \, a^{2} b^{5} x^{2} + 4 \, a^{3} b^{4} x + a^{4} b^{3}\right )}} \]
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\[ \int \frac {x^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\int \frac {x^{2}}{\left (\left (a + b x\right )^{2}\right )^{\frac {5}{2}}}\, dx \]
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Time = 0.20 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.44 \[ \int \frac {x^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {1}{2 \, b^{5} {\left (x + \frac {a}{b}\right )}^{2}} + \frac {2 \, a}{3 \, b^{6} {\left (x + \frac {a}{b}\right )}^{3}} - \frac {a^{2}}{4 \, b^{7} {\left (x + \frac {a}{b}\right )}^{4}} \]
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Time = 0.28 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.35 \[ \int \frac {x^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {6 \, b^{2} x^{2} + 4 \, a b x + a^{2}}{12 \, {\left (b x + a\right )}^{4} b^{3} \mathrm {sgn}\left (b x + a\right )} \]
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Time = 9.49 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.44 \[ \int \frac {x^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {\sqrt {a^2+2\,a\,b\,x+b^2\,x^2}\,\left (a^2+4\,a\,b\,x+6\,b^2\,x^2\right )}{12\,b^3\,{\left (a+b\,x\right )}^5} \]
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